10=-x^2+3x

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Solution for 10=-x^2+3x equation: 



10=-x^2+3x

We move all terms to the left:

10-(-x^2+3x)=0

We get rid of parentheses

x^2-3x+10=0

a = 1; b = -3; c = +10;
Δ = b2-4ac
Δ = -32-4·1·10
Δ = -31
Delta is less than zero, so there is no solution for the equation

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